2b^2-9b+7=0

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Solution for 2b^2-9b+7=0 equation:



2b^2-9b+7=0
a = 2; b = -9; c = +7;
Δ = b2-4ac
Δ = -92-4·2·7
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-5}{2*2}=\frac{4}{4} =1 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+5}{2*2}=\frac{14}{4} =3+1/2 $

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